\documentclass[11pt]{article} %\usepackage{amsbsy} % for \boldsymbol and \pmb %\usepackage{graphicx} % To include pdf files! \usepackage{amsmath} \usepackage{amsbsy} \usepackage{amsfonts} %\usepackage[colorlinks=true, pdfstartview=FitV, linkcolor=blue, citecolor=blue, urlcolor=blue]{hyperref} % For links \usepackage{fullpage} % Good for US Letter paper \topmargin=-0.75in \textheight=9.5in \usepackage{fancyhdr} \renewcommand{\headrulewidth}{0pt} % Otherwise there's a rule under the header \setlength{\headheight}{15.2pt} \fancyhf{} \pagestyle{fancy} \cfoot{Page \thepage {} of 2} % % \pagestyle{empty} % No page numbers \begin{document} %\enlargethispage*{1000 pt} \begin{flushright} Name \underline{\hspace{60mm}} \\ $\,$ \\ Student Number \underline{\hspace{60mm}} \end{flushright} \vspace{2mm} \begin{center} {\Large \textbf{STA 312 f2023 Quiz 3}}\\ \vspace{1 mm} \end{center} \noindent Let $X_1, \ldots, X_n$ be a random sample (that is, independent and identically distributed) from a Poisson distribution with parameter $\lambda>0$. You already know that the maximum likelihood estimate is $\widehat{\lambda} = \overline{X}$. We want to test $H_0: \lambda = \lambda_0$ versus $H_1: \lambda \neq \lambda_0$ with a large-sample likelihood ratio test. For this problem, the subset of the parameter space specified by the null hypothesis is a single point: $\Theta_0 = \{ \lambda_0 \}$. \begin{enumerate} \item (7 points) \label{Gsq} Write down and simplify the $G^2$ test statistic. A variety of ``simplified" answers can be correct. Your final answer is a formula. \textbf{Circle it}. \pagebreak %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% ~ \vspace{140mm} \item (3 points) \begin{enumerate} \item A random sample of size $n=49$ yields a sample mean of 4.2 and a sample standard deviation of 2.14. We want to test $H_0: \lambda=3$. Calculate your $G^2$ statistic from Question~\ref{Gsq}. Show a little work. The answer is a number. \textbf{Circle your answer}. \vspace{50mm} \item What are the degrees of freedom? The answer is a number. \vspace{5mm} \item The critical chi-squared value at $\alpha=0.5$ is $1.96^2 = 3.84$. Do you reject $H_0$? Answer Yes or No. \end{enumerate} \end{enumerate}\vspace{50mm} \end{document}